A 25.00 mL sample of HCl was titrated with 35.79 mL of 0.250 M KOH. The concentration of the HCl solution is:

Answer 1

volumebase*Normalitybase=volumeacid*Normalityacid

35.79*.250=25*x

x=35.79/100=.3579 M

Answer 2

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