Asked by Kay

A 25.00 mL sample of HCl was titrated with 35.79 mL of 0.250 M KOH. The concentration of the HCl solution is:
Answered by bobpursley
volumebase*Normalitybase=volumeacid*Normalityacid

35.79*.250=25*x

x=35.79/100=.3579 M
Answered by woo
the answer is ######
There are no AI answers yet. The ability to request AI answers is coming soon!