Asked by Cassie
Steve can you please show me how to do this problem?
What is the area of the shaded region in the given circle in terms of pi and in the simplest form?
the picture shown is of a circle with a triangle from 1 oclock to 3 oclock with a 60 deg opening. the side length of the triangle is 18m and the little part where the triangle and the edge of the circle meet between 1 and 3 oclock is the only part not shaded. The choices we have as answers are...
A. (270pi+54 sqrt3)m^2
B. (216pi+54 sqrt3)m^2
C. (270pi+108 sqrt3)m^2
D. (270pi+81 sqrt3)m^2
I hope you understand this explanation.
What is the area of the shaded region in the given circle in terms of pi and in the simplest form?
the picture shown is of a circle with a triangle from 1 oclock to 3 oclock with a 60 deg opening. the side length of the triangle is 18m and the little part where the triangle and the edge of the circle meet between 1 and 3 oclock is the only part not shaded. The choices we have as answers are...
A. (270pi+54 sqrt3)m^2
B. (216pi+54 sqrt3)m^2
C. (270pi+108 sqrt3)m^2
D. (270pi+81 sqrt3)m^2
I hope you understand this explanation.
Answers
Answered by
Steve
since the triangle is equilateral, the radius of the circle is 18.
so, your area is 5/6 of a circle plus the area of the triangle, which is 18^2/4 √3 = 81√3
so, your area is 5/6 of a circle plus the area of the triangle, which is 18^2/4 √3 = 81√3
Answered by
Cassie
Thank you Steve...
Answered by
!@#$%^&a with the bag
did u smash
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