HI STEVE,

Question

THANKS for your reply back it was the wrong answer the one you worked, yes a hard question,
here is an example of simultaneous questions.

x-2/3 + y-1/4 =13/12 (1)

2-x/2 + 3+y/3 =11/6 (2)

first step is to get rid of fractions.
in equation (1) the lcm of denominators is 12 .multiply each term by 12,

4(x-)+3(y-1) = 13
4x-8+3y-3= 13
4x+3y = 24 (3)
in equation (2) the lcm of denominator is 6.
multiply each term by 6,
3(2-x)+2(3+y)=11
6-3x+6+2y= 11
-3x+2y=-1 (4)
to eliminate y we multiply equation (3) by 2 and equation 940 by 3.
8x+6y=48(5)
-9x=6y=-3(6)
subtracting equation (6)from equation (5),
(8x-(-9x)+(6y-6y)= (48-(-3)
17x= 51
x= 3
try the previous question again please
thanks

Answer 1

I think you are referring to this earlier post by you
http://www.jiskha.com/display.cgi?id=1415787409

I agree with Steve's answer, I subbed his answer back in the original equation, and it worked.
Steve's solution was correct, perhaps you typed it incorrectly.

As to this new question ....
You MUST put in brackets so the question can be properly interpreted, (as Steve did for you)

You seem to be working it out as if brackets had been there but they must be there.