Asked by Sarah
If one pound (454g) of hexane combusts with 185 grams of oxygen which reactant is the limiting reactant and how many grams of carbon dioxide are produced?
My work: 454 g C6H14 * 1 mol C6H14/86.18 g C6H14 * 6 mol CO2/ 1 mol C6H14 * 44 g C02/ 1 mol CO2= 1390.7 g/ CO2
185 g O2 * 1 mol O2/ 32 g O2 * 6 mol CO2/(19/2) mol O2 * 44 .0g CO2/ 1 mol CO2= 160.65 g/CO2
Limiting factor is O2
My work: 454 g C6H14 * 1 mol C6H14/86.18 g C6H14 * 6 mol CO2/ 1 mol C6H14 * 44 g C02/ 1 mol CO2= 1390.7 g/ CO2
185 g O2 * 1 mol O2/ 32 g O2 * 6 mol CO2/(19/2) mol O2 * 44 .0g CO2/ 1 mol CO2= 160.65 g/CO2
Limiting factor is O2
Answers
Answered by
DrBob222
The process looks ok to me but you have too many significant figures in the answer. I would round that to 161 grams.
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