Asked by Millie
A 478.18g ice cube is taken out of the freezer at -8.5 degrees Celsius. how much heat s needed to turn it in to steam?
Answers
Answered by
DrBob222
q1 = heat needed to raise T from -8.5 to zero c.
q1 = mass ice x specific heat ice x (Tfinal-Tinitial)
q2 = heat needed to melt ice at Zero C and convert to liquid H2O.
q2 = mass ice x heat fusion
q3 = heat needed to raise T of water from zero C to 100 C
q3 = mass H2O x specific heat H2O x (Tfinal-Tinitial)_
q4 = heat needed to change liquid water at 100 C to steam at 100 C.
q4 = mass H2O x heat vaporization
Total = sum of individual qs.
q1 = mass ice x specific heat ice x (Tfinal-Tinitial)
q2 = heat needed to melt ice at Zero C and convert to liquid H2O.
q2 = mass ice x heat fusion
q3 = heat needed to raise T of water from zero C to 100 C
q3 = mass H2O x specific heat H2O x (Tfinal-Tinitial)_
q4 = heat needed to change liquid water at 100 C to steam at 100 C.
q4 = mass H2O x heat vaporization
Total = sum of individual qs.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.