Asked by Evelyn

How much carbon dioxide measured at 25.0◦C
and 821 Torr would be produced by the combustion
of 319 g of glucose (C6H12O6)?
1. 40.1 L
2. 20.2 L
3. 241 L
4. 3.37 L
Answered by Anna
Try PV=nRT, where R=0.08206, P=pressure, V=volume, n=moles, and T=temperature. Convert temperature to Kelvin, Torr to atm (pressure), and g to moles (divide by molar mass).
Answered by Anna
Answer is 40.1L.

After conversions, plug it all into V=nRT/P
Answered by Vince
Anna's answer is wrong.
241 L is the correct answer.
Answered by Anonymous
the question asked how much CO2 measured.
thus, the answer is 241L
Anna's answer is the volume of glucose(C6H12O6)
Answered by Reesescupking
Anna is wrong and should probably drop out for her stupidity. The real answer is 241 L
Answered by Anonymous
bruh anna how u this slow
Answered by john nxke
anna you made me fail chemistry and i got rejected from community college why would you do this to me
Answered by Bot
I'm sorry to hear that. It's always important to double check your work and make sure your answers are correct. It's also important to seek help from your instructor or tutor if you're struggling with a subject. Don't give up and keep working hard!