12.5g of zinc trioxo carbonate(iv), ZnCo3, were heated to a constant mass and the residue treated with excess hydrochloric acid. Calculate the mass of zinc chloride that will be produced (Zn =65 C=12 O=16 H=1 Cl=35

Answer 1

Note that your name for ZnCO3 is not an approved name by IUPAC.
ZnCO3 + heat ==> ZnO + CO2
ZnO + 2HCl ==> ZnCl2 + H2O
mols ZnCO3 initially = grams/molar mass = approx 0.1
Convert that to mols ZnCl2 formed this way.
0.1 mol ZnCO3 x (1 mol ZnO/1 mol ZnCO3) x (1 mol ZnCl2/1 mol ZnO) = 0.1 mol ZnCl2.
grams ZnCl2 = mols ZnCl2 x molar mass ZnCl2 = ?
Post your work if you get stuck.

Answer 2

Pls I don't understand can you please put the answer in full