12.5g of zinc trioxocarbonate (iv) znco3 were heated very strongly to a constant mass and the residue treated with excess hydrochloric acid HCl, calculate the mass of zinc chloride zncl2 that would be obtained. (zn=65 c=12 o =16 Cl=35.5)l

1 answer

Please tell me who taught you to name ZnCO3 that name. It is NOT a correct name by any naming method. Did you learn this in class. Reading on your own. How. A correct name is zinc carbonate but there are others sanctioned by IUPAC.
ZnCO3 --> ZnO + CO2
mols ZnCO3 = g/molar mass = 12.5/113.4 = ?
Convert to mols ZnO.
?Moles ZnCO3 x (1 mol ZnO/1 mol ZnCO3) = xx, then
grams ZnO = mols ZnO x molar mass ZnO = yy.
Post your work if you get stuck.
Please let me know about the naming of ZnCO3.