Asked by john
a 50g bullet is shot from a rifle at 900m/s
a) what is the KE of the bullet?
b) how much work is done on the bullet if it starts from rest?
Answers
Answered by
Anonymous
a) k.e = 1/2 mv^2
= 1/2(0.05)(900)^2
note 50g converted into kg
= 1/2(0.05)(900)^2
note 50g converted into kg
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