Asked by Anonymous
Find and equation of the circle with center at (0,0) that passes through the poijt (5,2)
Answers
Answered by
Reiny
Which method have you been taught to find the circle for this basic question?
Answered by
Anonymous
I haven't learned how to do this.
Answered by
Reiny
I don't understand.
Are you in a course where this on the curriculum?
How do they expect you to do this if you have not learned it, or have not been taught?
Are you in a course where this on the curriculum?
How do they expect you to do this if you have not learned it, or have not been taught?
Answered by
Anonymous
I don't know but that's why I'm asking on this website.
Answered by
Reiny
basic equation with centre (0,0) and radius r is
x^2 + y^2 = r^2
since (5,2) lies on this
25 + 4 = r^2 = 29
x^2 + y^2 = 29
x^2 + y^2 = r^2
since (5,2) lies on this
25 + 4 = r^2 = 29
x^2 + y^2 = 29