Question

What volume of carbon tetrachloride (density = 2.71 g/mL) contains 2.46x10^25 chlorine atoms?

Answer 1

one C per molecule?
6.02 * 10^23 molecules per mol

2.46 * 10^25 molecules *(1/6.02*10^23)
= 40.9 mols

How many grams?
40.9 * (12 + 4(35.5) )

what volume?
grams / 2.71 g/mL

Answer 2

but how do you get the right amount of mL?

I did: 2.46x10^25 Cl atoms x 1 atom/4 atoms x 1 mol/6.02x10^23 x 154 g/1 mol x 1 mL/2.71 g

And the correct answer is apparently 572 mL when I got 581 mL.