Asked by danna
what volume of carbon dioxide is formed when 11 of CS2 reacts with 18 L O2 to produce carbon dioxide gas and sulfur dioxide gas at STP?
Answers
Answered by
DrBob222
This is a limiting reagent problem. You know that because you have amounts given for BOTH reactants.
CS2 + 3O2 ==> CO2 + 2SO2
Is that 11 L CS2? If so you can take a shortcut and not convert L to mols but use L directly. As follows:
L CO2 formed will be
L CS2 x (1 mol CO2/1 mol CS2) = 11 x (1/1) = 11 L CO2 (If we had all of the O2 we needed.
If we had 18 L O2 the volume of CO2 formed will be
L O2 x (1 mol CO2/3 mols O2) = 18 x (1/3) = 6 L CO2 (if we had all of the CS2 need).
You get two different answers this way which means one of them is wrong; the correct answer in limiting reagent problems is ALWAYS the smaller value; therefore, 6L CO2 will be the volume of CO2 formed at STP.
CS2 + 3O2 ==> CO2 + 2SO2
Is that 11 L CS2? If so you can take a shortcut and not convert L to mols but use L directly. As follows:
L CO2 formed will be
L CS2 x (1 mol CO2/1 mol CS2) = 11 x (1/1) = 11 L CO2 (If we had all of the O2 we needed.
If we had 18 L O2 the volume of CO2 formed will be
L O2 x (1 mol CO2/3 mols O2) = 18 x (1/3) = 6 L CO2 (if we had all of the CS2 need).
You get two different answers this way which means one of them is wrong; the correct answer in limiting reagent problems is ALWAYS the smaller value; therefore, 6L CO2 will be the volume of CO2 formed at STP.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.