a ball is thrown into the air with an upward velocity of 32 ft per second. Its height h in feet after t seconds is given by the function h(t)=-16t^2 +32t+6. How long does it take the ball to reach its maximum height? What is the balls maximum height?

Question

a ball is thrown into the air with an upward velocity of 32 ft per second. Its height h in feet after t seconds is given by the function h(t)=-16t^2 +32t+6. How long does it take the ball to reach its maximum height? What is the balls maximum height?
a- 22 ft 1.0 second
b- 22 ft 2.0 seconds
c- 44 ft 2.17 seconds
d- 11 ft 2.17 seconds

my answer is c or d

bobpursley · Accepted Answer

h(t)=16t(2-t) + 6 so note that at t=0, and t=2 h(t) is 6, the starting point. So max t occurs then at t=1, halfway (it is a parabola). max h=16(1)+6=22

Steve · Answer

so it would be 22 ft after 1 second

bobpursley · Answer

yes

Steve · Answer

Thank you very much at 68 trying to help grandson I'm stretching a bit to when I took this

Diana · Answer

Sports. A baseball is thrown into the air with upward velocity of 30 ft / s. Its height h, in feet, after t seconds is given by the function h = -16t ^ + 30t + 6. How long will it take the ball to reach its maximum height? What is the ball's maximum height? What is the range of the function?