Question

what would the domain be if i had a problem with the denominator as x^3?

Answer 1

YOu cant have x=0 in the domain.

Answer 2

it is just basic factorising but im not sure how u do it.

x2-5x =

by the way that is meant to be x squared, minus 5 x.

also 3a2 - 6a =

Answer 3

First, if you have a question, it is much better to put it in as a separate post in <Post a New Question> rather than attaching it to a previous question, where it is more likely to be overlooked.

Use a carat (^) to indicate a power.

x^2-5x = x(x-5)

3a^2-6a = 3a(a-2)

I hope this helps. Thanks for asking.