Asked by anonymous
what would the domain be if i had a problem with the denominator as x^3?
Answers
Answered by
bobpursley
YOu cant have x=0 in the domain.
Answered by
hannah
it is just basic factorising but im not sure how u do it.
x2-5x =
by the way that is meant to be x squared, minus 5 x.
also 3a2 - 6a =
x2-5x =
by the way that is meant to be x squared, minus 5 x.
also 3a2 - 6a =
Answered by
PsyDAG
First, if you have a question, it is much better to put it in as a separate post in <Post a New Question> rather than attaching it to a previous question, where it is more likely to be overlooked.
Use a carat (^) to indicate a power.
x^2-5x = x(x-5)
3a^2-6a = 3a(a-2)
I hope this helps. Thanks for asking.
Use a carat (^) to indicate a power.
x^2-5x = x(x-5)
3a^2-6a = 3a(a-2)
I hope this helps. Thanks for asking.