Asked by anonymous
                what would the domain be if i had a problem with the denominator as x^3?
            
            
        Answers
                    Answered by
            bobpursley
            
    YOu cant have x=0 in the domain.
    
                    Answered by
            hannah
            
    it is just basic factorising but im not sure how u do it.
x2-5x =
by the way that is meant to be x squared, minus 5 x.
also 3a2 - 6a =
    
x2-5x =
by the way that is meant to be x squared, minus 5 x.
also 3a2 - 6a =
                    Answered by
            PsyDAG
            
    First, if you have a question, it is much better to put it in as a separate post in <Post a New Question> rather than attaching it to a previous question, where it is more likely to be overlooked.
Use a carat (^) to indicate a power.
x^2-5x = x(x-5)
3a^2-6a = 3a(a-2)
I hope this helps. Thanks for asking.
    
Use a carat (^) to indicate a power.
x^2-5x = x(x-5)
3a^2-6a = 3a(a-2)
I hope this helps. Thanks for asking.
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