Asked by Alice
A force of 112 N acts on 35 kg box which moves at a steady speed across the floor. The force is directed 40 degrees above the ground. How to state Newton's second law using x components and y components? x: -Fa(cos40) -Ff=ma and y: -Fa(sin40)+Fn-Fg=0? How do you calculate force of friction and normal force from this information? How do you find the force the box is acting on the floor (magnitude and direction)?