Asked by krome
Find the 6th term of the arithmetic sequence given an = (1/5)an-1, given a1 = 20
Answers
Answered by
Reiny
If I read this correctly as
a<sub>n</sub> = (1/5) a<sub>n-1</sub> , where <sub>1</sub> = 20
then
<sub>1</sub> = 20
<sub>2</sub> = 4
<sub>3</sub> = 4/5
etc
then this not an arithmetic but rather a geometric sequence
with a = 20 , r = 1/5
t<sub>6</sub> = ar^5 = 20(1/5)^5 = 20/3125 = 4/625
a<sub>n</sub> = (1/5) a<sub>n-1</sub> , where <sub>1</sub> = 20
then
<sub>1</sub> = 20
<sub>2</sub> = 4
<sub>3</sub> = 4/5
etc
then this not an arithmetic but rather a geometric sequence
with a = 20 , r = 1/5
t<sub>6</sub> = ar^5 = 20(1/5)^5 = 20/3125 = 4/625
Answered by
Thomas
Give the arithmetic sequence -7 ,-1, 5,11. Find the a.32term b.42 term.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.