Asked by Kiki

Find the 6th term of the arithmetic sequence with a9=120 and a14=195
Answered by Reiny
a9 = 120 ----> a + 8d = 120
a14 = 195 ---> a + 13d = 195
subtract them
5d = 75
d = 15
then a+8(15) = 120
a = 0

so term(6) = a+5d = 0 + 5(15) = 75
Answered by Anonymous
find the 6th term of an arithmetic sequence with a9 = 12 and a14 = 195
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