Question
a plane traveling at 400 mph leaves the philadelphia airport at 1pm heading due east. two hours later a second plane traveling at 600 mph leaves the airport heading in the same direction. at what time does the second plane overtake the first?
Answers
When the 2nd overtakes the first, they will have travelled the same distance:
let the time of the first plane since 1:00 pm be t hrs
distance covered by first plane = 400t miles
let the time of the 2nd plane be t-2 hrs
distance covered by 2nd plane = 600(t-2)
400t = 600(t-2)
400t = 600t - 1200
-200t = -1200
t = 6
so time since 1:00 is 6 hrs, or the time will be 7:00 pm
let the time of the first plane since 1:00 pm be t hrs
distance covered by first plane = 400t miles
let the time of the 2nd plane be t-2 hrs
distance covered by 2nd plane = 600(t-2)
400t = 600(t-2)
400t = 600t - 1200
-200t = -1200
t = 6
so time since 1:00 is 6 hrs, or the time will be 7:00 pm
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