Question

I'm don't understanding how to solve this question:

The graph of a line passes through the x-intercept of y-20=2/11(x-31) and is perpendicular to the line y=1/7x+7 . The equation of the line, written in Slope-Point form, is y-p = m(x-q). what is the value of m*q ?

Answer 1

just take it step by step. The x-intercept is where y=0, so x = -79

Now, your line must have a slope of -7, so its equation is

y-0 = -7(x+79)
mq = -7(79) = -553

Answer 2

How to get -79 ?