Question
A taxi hurries for 1 hour 3 minutes wit a constant speed of 118km/hr and then for another 1 hour 9 minutes with a constant speed of 40km/hr. What is its average speed for the total trip?
Answers
d = V1*T1 + V2*T2 = 118*1.05 + 40*1.15 =
169.9 km.
Vavg = d/(T1+T2) = 169.9/2.20 = 77.2 km/h.
169.9 km.
Vavg = d/(T1+T2) = 169.9/2.20 = 77.2 km/h.
77.2
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