Question
For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6. Show your work.
y = -2x2 + 2x +2
-(1/2)y=x^2-x-1
(-1/2)y+1=x^2-x
(-1/2)y+1=(x-1/2)^2-14
(-1/2)y=(x-1/2)^2-5/4
y=-2(x-1/2)^2+5/2
Is this right ?
y = -2x2 + 2x +2
-(1/2)y=x^2-x-1
(-1/2)y+1=x^2-x
(-1/2)y+1=(x-1/2)^2-14
(-1/2)y=(x-1/2)^2-5/4
y=-2(x-1/2)^2+5/2
Is this right ?
Answers
2 x^2 - 2 x - 2 = -y
x^2 - x -1 = -(y/2)
x^2 - x = -y/2 + 1
x^2 - x + 1/4 = -y/2 + 1 + 1/4
(x- 1/2)^2 = -(1/2) (y - 5/2)
vertex at ( 1/2 , 5/2 )
if x = 6
y = - 2(36) + 12 + 2 = -58
===================
check
(5.5)^2 =? -1/2 (-60.5) ???
30.25 = 30.25 sure enough :)
x^2 - x -1 = -(y/2)
x^2 - x = -y/2 + 1
x^2 - x + 1/4 = -y/2 + 1 + 1/4
(x- 1/2)^2 = -(1/2) (y - 5/2)
vertex at ( 1/2 , 5/2 )
if x = 6
y = - 2(36) + 12 + 2 = -58
===================
check
(5.5)^2 =? -1/2 (-60.5) ???
30.25 = 30.25 sure enough :)
Thank you :)
which one is the right answer and work
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