The integral of (x^2-4secxtanx) dx= I got x^3/3-4secx+c

integral of 1/((x^2+1)^2) dx

integral from 3 to 6 (x^4+4)/(x) dx=

integral of (2x) / [(x+2)(x+1)]

if the integral ( [ ) ([ f(t) ,t, 0, 8) = k Find [ (3x^2f(x^3), x, 0, 2)

integral [((log(1+x))/(1 x^(2)))] .... limits: [0,1]

The integral from 1 to 5 of 1/x^2*(times) the square root of 1+(1/x)dx. i've had tried this problem...

the integral from 0 to pi/2 of sin^5(x)cos^18(x)

the integral from -2 to 1 of 1/(x^2 +4x+13)

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