Asked by Brandon
A bag contains 1 red, 7 black and two yellow marbles. What is the probability of selecting 1 yellow marble, not replacing it then selecting another yellow marble?
How do you solve this?
How do you solve this?
Answers
Answered by
Steve
there are initially 2 yellows out of a total of 10 marbles.
chance of yellow on 1st draw: 2/10
with that yellow gone, there is now only 1 yellow out of 9 total, so the chance of a yellow on the 2nd draw is 1/9
So, the total probability is 2/10 * 1/9
chance of yellow on 1st draw: 2/10
with that yellow gone, there is now only 1 yellow out of 9 total, so the chance of a yellow on the 2nd draw is 1/9
So, the total probability is 2/10 * 1/9
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