Asked by sha
a car moving at 30 m/s slows to a speed of 10 m/s in a time of 5 s. determine a.) the acceleration of the car (b). the distance it moves in the third second.
Answers
Answered by
Henry
a. V = Vo + a*t
Vo = 30 m/s
V = 10 m/s
t = 5s.
Solve for a. It will be negative.
b. d = Vo*t + 0.5a*t^2
Vo = 30 m/s
V = 10 m/s
t = 5s.
Solve for a. It will be negative.
b. d = Vo*t + 0.5a*t^2
Answered by
wonde
-4m/s
Answered by
Anonymous
656
Answered by
PUNDE FELLA
a. V = Vo + a*t
Vo = 30 m/s
V = 10 m/s
t = 5s.
Solve for a. It will be negative.
b. d = Vo*t + 0.5a*t^2
Vo = 30 m/s
V = 10 m/s
t = 5s.
Solve for a. It will be negative.
b. d = Vo*t + 0.5a*t^2
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