Asked by marie haynes
5oocm3 of 1.0 mol dm3 of sodium hydroxide solution at room temperature was placed in a styrofoam cup and 25cm3 of 2.0 mol-dm3 of hydrochloric acid was added at the same temperature.The temperature rose by 15.2 degrees celsius. Calculate the heat of neurtralization
Answers
Answered by
DrBob222
NaOH + HCl ==> NaCl + H2O
mols NaOH = M x L = 1.0 x 0.5 = 0.5
mols HCl = M x L = 0.025 x 2 = 0.05
So HCl is the limiting reagent.
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
Find q. That is q/0.05 mol H2O.
Convert to kJ/mol
This is the right way to do it but I don't think it gives the correct answer. Check the problem to be sure the numbers are right. Could that be 1.52 C and not 15.2?
mols NaOH = M x L = 1.0 x 0.5 = 0.5
mols HCl = M x L = 0.025 x 2 = 0.05
So HCl is the limiting reagent.
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
Find q. That is q/0.05 mol H2O.
Convert to kJ/mol
This is the right way to do it but I don't think it gives the correct answer. Check the problem to be sure the numbers are right. Could that be 1.52 C and not 15.2?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.