Asked by rose
factor polynomial by grouping 3z^3+2z-12z^2-8
Answers
Answered by
kudum
3z^3+2z-12z^2-8
= 3z^3 -12Z^2 + 2z -8
= 3z^2(z-4)+2(z -4)
=(z-4)(3z^2 +2)
= 3z^3 -12Z^2 + 2z -8
= 3z^2(z-4)+2(z -4)
=(z-4)(3z^2 +2)
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