Find the general solution of the DE. Write your solution explicitly. y'=(y^(2)+y^(2)cosx)^2

Answer 1

what, have you forgotten your algebra I?

y' = (y^2 + y^2 cosx)^2
y' = y^4 (1+cosx)^2
y'/y^4 = (1+cosx)^2
dy/y^4 = (1+cosx)^2 dx
-1/3 y^-3 = 1/4 (6x+8sinx+sin2x) + c
y = -∛(4/(3(6x+8sinx+sin2x) + c))