Asked by Elan

Find all solutions (if they exist)for the given equation on the interval [0,2pi)
cos^2x-5sinx+5=0

Answers

Answered by Steve
cos^2x-5sinx+5=0
1-sin^2x - 5sinx + 5 = 0
sin^2x + 5sinx - 6 = 0
(sinx+6)(sinx-1) = 0
so,
sinx = -1/6 or 1
Now you can find x. Watch for signs in quadrants.
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