Question

Find the solutions to x2 = 27
x=$3/3
x=$9/3
x=$319
x=÷9/2

Answer 1

To solve the equation \( x^2 = 27 \), we can follow these steps:

1. Take the square root of both sides:
\[
x = \pm \sqrt{27}
\]

2. Simplify \(\sqrt{27}\):
\[
\sqrt{27} = \sqrt{9 \cdot 3} = \sqrt{9} \cdot \sqrt{3} = 3\sqrt{3}
\]

3. Therefore, the solutions are:
\[
x = 3\sqrt{3} \quad \text{and} \quad x = -3\sqrt{3}
\]

Now, let's compare this with the options provided in your question:
- \(x = \frac{3}{3}\) simplifies to \(1\), which is not a solution.
- \(x = \frac{9}{3}\) simplifies to \(3\), which is not a solution.
- \(x = 319\) is not a solution.
- \(x = \div 9/2\) is not a valid expression.

None of the options you provided are correct solutions for the equation \( x^2 = 27 \). The correct solutions are:
\[
x = 3\sqrt{3} \quad \text{and} \quad x = -3\sqrt{3}
\]