Question
For the titration of 50.00mL of 0.1000 M ammonia with 0.1000 M HCl, calculate the pH
(a) before the addition of any HCl solution
(b) after 20.00mL of the acid has been added
(a) before the addition of any HCl solution
(b) after 20.00mL of the acid has been added
Answers
At the beginning you have pure NH3 solution.
......NH3 + H2O ==> NH4^+ + OH-
I.....0.1............0.......0
C......-x............x.......x
E.....0.1-x...........x......x
Plug the E line into the Kb expression and solve for x = OH, then convert to pH.
For part b. You started with how many mols of each.
mols NH3 = M x L = ? about 0.005
mols HCl = M x L = ? about 0.002
So you have 0.003 M NH3 left no HCl in excess and you formed 0.002 mols NH4Cl.
Use the Henderson-Hasselbalch equation for buffers and calculate the pH.
pH = pKa + log (base)/(acid)
......NH3 + H2O ==> NH4^+ + OH-
I.....0.1............0.......0
C......-x............x.......x
E.....0.1-x...........x......x
Plug the E line into the Kb expression and solve for x = OH, then convert to pH.
For part b. You started with how many mols of each.
mols NH3 = M x L = ? about 0.005
mols HCl = M x L = ? about 0.002
So you have 0.003 M NH3 left no HCl in excess and you formed 0.002 mols NH4Cl.
Use the Henderson-Hasselbalch equation for buffers and calculate the pH.
pH = pKa + log (base)/(acid)
take it ez maaaan
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