mols AgNO3 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols AgNO3 to mols AgCl.
Now convert mols AgCl to grams. grams AgCl = mols AgCl x molar mass AgCl.
2 AgNO3 + BaCl2 → 2 AgCl + Ba(NO3)2
Using the coefficients in the balanced equation, convert mols AgNO3 to mols AgCl.
Now convert mols AgCl to grams. grams AgCl = mols AgCl x molar mass AgCl.
1. Start by finding the molar mass of AgNO3. This can be calculated by adding up the atomic masses of each element in the compound:
Ag: 107.87 g/mol
N: 14.01 g/mol
O: 16.00 g/mol (x3 since there are 3 oxygen atoms)
Molar mass of AgNO3 = (1 x Ag) + (1 x N) + (3 x O) = 107.87 g/mol + 14.01 g/mol + 48.00 g/mol = 169.88 g/mol
2. Calculate the number of moles of AgNO3 using the given mass and the molar mass:
Moles of AgNO3 = mass of AgNO3 / molar mass of AgNO3
Moles of AgNO3 = 15.4 g / 169.88 g/mol = 0.0906 mol
3. According to the balanced chemical equation, the stoichiometric ratio between AgNO3 and AgCl is 2:2, meaning that for every 2 moles of AgNO3, 2 moles of AgCl are produced.
4. Using the stoichiometric ratio, calculate the number of moles of AgCl produced:
Moles of AgCl = (moles of AgNO3) x (moles of AgCl / moles of AgNO3)
Moles of AgCl = 0.0906 mol x (2 mol AgCl / 2 mol AgNO3) = 0.0906 mol
Therefore, 15.4 g of AgNO3 will produce 0.0906 moles of AgCl.