Asked by Mike
What is the pH of the resulting solution when 0.20 mole of NaF and 0.05 mole HCl are
added to 100 mL water?
The Ka for HF is 3.95x10^-4M
added to 100 mL water?
The Ka for HF is 3.95x10^-4M
Answers
Answered by
DrBob222
.........F^- + H^+ ==> HF
I.......0.2....0........0
add...........0.05........
C......-0.05..-0.05.....0.05
E......0.15....0.......0.05
Use the Henderson-Hasselbalch and calculate pH.
I.......0.2....0........0
add...........0.05........
C......-0.05..-0.05.....0.05
E......0.15....0.......0.05
Use the Henderson-Hasselbalch and calculate pH.
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