Asked by Akki
Find relative Minimum and Maximum
f'(x) = (9-4x^2)/ (x+1)^1/3
f'(x) = (9-4x^2)/ (x+1)^1/3
Answers
Answered by
Steve
the extrema occur where f' = 0
So, where do you have 9-4x^2 = 0?
With those values, you can evaluate the integral to find the value of f(x) there
So, where do you have 9-4x^2 = 0?
With those values, you can evaluate the integral to find the value of f(x) there
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.