Question
Find relative Minimum and Maximum
f'(x) = (9-4x^2)/ (x+1)^1/3
f'(x) = (9-4x^2)/ (x+1)^1/3
Answers
Steve
the extrema occur where f' = 0
So, where do you have 9-4x^2 = 0?
With those values, you can evaluate the integral to find the value of f(x) there
So, where do you have 9-4x^2 = 0?
With those values, you can evaluate the integral to find the value of f(x) there