1) C2H2O4(aq) = H+ (aq) + C2HO4- (aq); Keq = 6.5E-2

Question

2) C2O42- (aq) + H+ (aq) = C2HO4- (aq); Keq = 1.64E+4

then what is the equilibrium constant for the following reaction: C2H2O4(aq) = 2H+ (aq) + C2O42- (aq)?


Keq = 1070

Keq = 227

Keq = 2.21E-4

Keq = 3.96E-6

Keq = 6.30E-3

Answer 1

Add eqn 1 to the REVERSE of eqn 2.
k1 = Keq for eqn 1.
k2 = Keq for eqn 2.
k' = keq for the REVERSE of eqn 2 = 1/k2

When you add equilibrium equations you multiply the k values so
k new rxn = k1*k' = k1*(1/k2) = ?