lets think. It could be CH4, or C2H4 , or C6H6, or octane, C8H18.
Now the ratios of moles of carbon and hydrogen are different in each.
Looking at C8H18., the moles of H are 18/8 moles of C
Carbon moles: 1/atomicmassC
Hydrogen: .033597/atomicmassH
Hydrogen moles also equal 18/8 moles C
so 18/8 * 1/atomicmassC=.0033597/AtomicmassH
solving for atomic mass H, then
atomic massH= .0033597*atomicmassC*8/18
that works out to about...0.018. Well, that is certainly not the compound.
So I suspect you need to know which compound was formed.
.033597 grams of hydrogen is combined with 1.000grams of of carbon . calculate the atomic mass of hydrogen
2 answers
I think something is amiss in this problem. Let's go the other way.
mols C = 1/12 = 0.083333
mols H = 0.033597/1.00794 = 0.03333
ratio is C2.48 to H1.00 which rounds to C5H2 and this is an unlikely hydrocarbon. So I don't think all of the looking in the world will help.
mols C = 1/12 = 0.083333
mols H = 0.033597/1.00794 = 0.03333
ratio is C2.48 to H1.00 which rounds to C5H2 and this is an unlikely hydrocarbon. So I don't think all of the looking in the world will help.