How many grams of hydrogen are released by the reaction of 1.00 g of aluminum with excess potassium hydroxide solution assuming 100% yield

Answer 1

2KOH + Al + 6H2O--> 2KAl(OH)4 + 3H2

mols Al = grams/molar mass = ?
Use the coefficients in the balanced equation to convert mols Al to mols H2
Now convert mols H2 to grams. g = mols x molar mass