Asked by kudu
Solve the equation: 2cos2θ = 1 for 0° ≤ θ ≤ 360.
2θ = cos-1(1/2)
2θ = 60°
θ= 30,210 330
2θ = cos-1(1/2)
2θ = 60°
θ= 30,210 330
Answers
Answered by
Steve
2θ = 60,330,420,690,...
θ = 30,115,210,345,...
θ = 30,115,210,345,...
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