Asked by Ian
                Integrate from 1 to 5 of (3x-5)^5 dx = Integrate from a to b of f(u) du
where (I have solved this part)
u = 3x-5
du = 3
a = 0
b = 12
The original value of the integral is 165888 via calculator
here's my last question, and it has to be in terms of u:
f(u) = ? (Again, in terms of u)
I originally thought it was 5(u)^4, then tried u^5, but to no avail. What am I doing wrong?
            
        where (I have solved this part)
u = 3x-5
du = 3
a = 0
b = 12
The original value of the integral is 165888 via calculator
here's my last question, and it has to be in terms of u:
f(u) = ? (Again, in terms of u)
I originally thought it was 5(u)^4, then tried u^5, but to no avail. What am I doing wrong?
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