Question

Use any method to solve the following equations, giving your answers to 2 decimal places where necessary. If an equation has no real roots, state this is so.

1. x2-5x+7=0

2. (3x-4)=(4x-3)2

Answer 1

1. This is already in standard form. You should be able solve that equation from what you've learned.

2. Here it is convenient to substitute.

y = 4x-3

Then

x = 1/4(y+3) -------->

3x - 4 = 3/4 (y+3) -4 =

3/4 y - 7/4

So, the equation is:

3/4 y - 7/4 = y^2 -------->

4 y^2 - 3 y + 7= 0