1. This is already in standard form. You should be able solve that equation from what you've learned.
2. Here it is convenient to substitute.
y = 4x-3
Then
x = 1/4(y+3) -------->
3x - 4 = 3/4 (y+3) -4 =
3/4 y - 7/4
So, the equation is:
3/4 y - 7/4 = y^2 -------->
4 y^2 - 3 y + 7= 0
Use any method to solve the following equations, giving your answers to 2 decimal places where necessary. If an equation has no real roots, state this is so.
1. x2-5x+7=0
2. (3x-4)=(4x-3)2
1 answer
2 answers