Asked by Anonymous
Solve using any method.
1. 2x^2+5x-3=0
2. -x^2+x+1=0
Answers
Answered by
Damon
(2x-1)(x+3) = 0 --> 1/2 and -3
x^2 - x - 1 = 0
x = [1 +/- sqrt (1+4) ]/2
= 1/2 +/- (1/2) sqrt 5
x^2 - x - 1 = 0
x = [1 +/- sqrt (1+4) ]/2
= 1/2 +/- (1/2) sqrt 5
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