Asked by pp
Consider the following equation, which represents the combustion of hydrogen sulfide.
2H2S(g)+3O2(g)¨2SO2(g)+2H2O(g)
What volume, in liters, of SO2 is formed when 120L of H2S(g) is burned? Assume that both gases are measured under the same conditions.
2H2S(g)+3O2(g)¨2SO2(g)+2H2O(g)
What volume, in liters, of SO2 is formed when 120L of H2S(g) is burned? Assume that both gases are measured under the same conditions.
Answers
Answered by
DrBob222
You should find the arrow key on your computer and use it.
When using gases at the same T and P one can use a shortcut procedure in which the volume (in L) is used directly as if it were mols.
So all you need to do is to convert 120 L H2S to SO2.
120 L SO2 x (2 mols SO2/2 mols H2S) \ 120 x 2/2 = 120 L SO2 formed.
When using gases at the same T and P one can use a shortcut procedure in which the volume (in L) is used directly as if it were mols.
So all you need to do is to convert 120 L H2S to SO2.
120 L SO2 x (2 mols SO2/2 mols H2S) \ 120 x 2/2 = 120 L SO2 formed.
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