Asked by Arman
                "Find the total energy lost by the contents of a Styrofoam picnic cooler when a 3.60 kg block of ice placed inside the cooler completely melts (at 0 Celsius). The ice had an initial temperature of -10.00 Celsius."
I did this question and i got 73080J but I'm not sure if i did it right, can u please tell me the steps!!!
thanks in advance
            
        I did this question and i got 73080J but I'm not sure if i did it right, can u please tell me the steps!!!
thanks in advance
Answers
                    Answered by
            DrBob222
            
    q1 = heat to raise T from -10 to zero.
q1 = mass ice in grams x specific heat solid ice x 10
q2 = heat to melt ice
q2 = mass ice x heat fusion.
Add q1 + q2 = total q.
    
q1 = mass ice in grams x specific heat solid ice x 10
q2 = heat to melt ice
q2 = mass ice x heat fusion.
Add q1 + q2 = total q.
                    Answered by
            Arman
            
    q1=72360J n q2=21672
q=94032J
is that right DrBob222
    
q=94032J
is that right DrBob222
                    Answered by
            DrBob222
            
    No. The 72,360 J is right for the q1 part. I don't know where the 21,573 came from.
    
                    Answered by
            DK
            
    For q2 I got 1204.66 (rounded) but now I’m confused a bit 
    
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