Arman

"Find the total energy lost by the contents of a Styrofoam picnic cooler when a 3.60 kg block of ice placed inside the cooler completely melts (at 0 Celsius). The ice had an initial temperature of -10.00 Celsius." I did this question and i got 73080J but...

"Find the total energy lost by the contents of a Styrofoam picnic cooler when a 3.60 kg block of ice placed inside the cooler completely melts (at 0 Celsius). The ice had an initial temperature of -10.00 Celsius." My ans are q1=72360J n q2=21672 q=94032J...

What is the domain of this need help! y = x^2+3x-4

i. (C2O4)-2 Loss of electrons.... ii. (MnO4)-1: 0.0150M*.0178L = mol(MnO4)-1 =>2.67*10^-4 mol (C2O4)-2: 2.67*10^-4 mol * 5(C2O4)/2(MnO4) (ratio) =>6.68*10^-4 mol iii. 6.68*10^-4 mol * 5 (100.ml/20.ml=5) =>3.34*10^-3 mol iv. 3.34*10^-3 mol * 97.032gfm = 0....

q1=72360J n q2=21672 q=94032J is that right DrBob222

s = ut + 1/2 at^2.............since the initial velocity down u = 0 100 = 0 + 1/2(9.81)t^2 t = 4.51 sec again s = ut + 1/2 at^2...........this time horizontally s = distance = (40)(4.51) + 1/2(0)(4.51)^2................Notice the acceleration = 0 s = 180....

1.83 x 10^4 L