Question

Please help solve for x

A.7^x+(4)(7^x) =245

B.x-|x+20=0

C.1+3/(x+1)=x

Simplify

D.(|24 +2|6 + |54 / |96 - |6

Keys: |=square root, /over or divided by

Answer 1

7^x + 4*7^x = 245
5*7^x = 245
7^x = 49
since 49 = 7^2, x=2

x-√x+20 = 0
think of this as
(√x)^2 - √x + 20 = 0
I think you must have a typo. It is much better if you have

(√x)^2 - √x - 20 = 0
(√x-5)(√x+4) = 0
√x = 5 or √x = -4
since √x is always positive, the only solution is
√x = 5
x = 25

1 + 3/(x+1) = x
(x+1) + 3 = x(x+1)
x^2-4 = 0
(x-2)(x+2) = 0
x = -2 or 2

Mismatched parentheses. I will assume you meant

(√24 + 2√6 + √54)/(√96 - √6)
If you factor out the perfect squares, you have
(2√6 + 2√6 + 3√6)/(4√6 - √6)
7√6 / 3√6
7/3

Answer 2

Thank you very much steve god bless you