Asked by kudu
The area of a rhombus is 60cm^2. Given that one of its diagonals is 15 cm long, calculate the perimeter of the rhombus.
Answers
Answered by
Reiny
area of a rhomus = (1/2)(product of its diagonals)
let the other diagonal be a
(1/2)(15a) = 60
15a= 120
a = 8
So let's find the hypotenuse of one of the right-angled triangles formed by the intersection of its diagonals
base = 4, height = 7.5
if h is the hypotenuse,
h^2 = 4^2 + 7.5^2
h = 8.5
so perimeter = 4(8.5) = 34 cm
let the other diagonal be a
(1/2)(15a) = 60
15a= 120
a = 8
So let's find the hypotenuse of one of the right-angled triangles formed by the intersection of its diagonals
base = 4, height = 7.5
if h is the hypotenuse,
h^2 = 4^2 + 7.5^2
h = 8.5
so perimeter = 4(8.5) = 34 cm
Answered by
stanley
34
Answered by
Mohamednur Awes
Where is 8.5 coming from
Answered by
Mohamednur Awes
7.5 is from where?
Answered by
Jerry
7.5 is half the diagonal which was 15š¤„thank me later
Answered by
Samuel
Where 7.5
where 7.5 come from
where 7.5 come from
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