Question
a rhombus has an area of 50 cm^2 and an internal angle of size 63 . find the lenght of its sides.
Answers
drwls
Rhombus area = a^2 sin A
where a is the side length and A is an internal angle at a corner. (Either the acute or the obtuse angle could be used, since that are supplementary)
Solve a^2 sin 63 = 50 to get since length a.
a^2 = 50/0.891
a = ____ cm
where a is the side length and A is an internal angle at a corner. (Either the acute or the obtuse angle could be used, since that are supplementary)
Solve a^2 sin 63 = 50 to get since length a.
a^2 = 50/0.891
a = ____ cm
Mota
thank u
:)
:)