Asked by Rishi
Determine the Final state and temperature of 100g of water originally at 25 degree C after 50 kJ of heat have been added to it.
Answers
Answered by
DrBob222
heat needed to raise T from 25C to 100 C.
q = mass H2O x specific heat H2O x (75)
q = approx 32,000 J (BUT THAT'S APPROXIMATE--YOU NEED TO GET A BETTER ANSWER)
That leaves 50,000-32,000 to be used to convert to steam.
q to convert to steam = mass x heat vap
APPROX 18,000 = mass H2O x heat vaporization.
Look up heat vap and solve for mass H2O that can be converted to steam.
You will have part liquid H2O @ 100 C and part steam at 100 C.
The remaining heat can heat the steam to an elevated temperature but no more liquid water can be converted to steam.
Therefore, your answer will be x grams liquid H2O at 100C, y grams steam at some T above 100.
q = mass H2O x specific heat H2O x (75)
q = approx 32,000 J (BUT THAT'S APPROXIMATE--YOU NEED TO GET A BETTER ANSWER)
That leaves 50,000-32,000 to be used to convert to steam.
q to convert to steam = mass x heat vap
APPROX 18,000 = mass H2O x heat vaporization.
Look up heat vap and solve for mass H2O that can be converted to steam.
You will have part liquid H2O @ 100 C and part steam at 100 C.
The remaining heat can heat the steam to an elevated temperature but no more liquid water can be converted to steam.
Therefore, your answer will be x grams liquid H2O at 100C, y grams steam at some T above 100.
Answered by
fhfdg
45
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