Asked by Lindsey
Determine the final temp when 45.8g of aluminum at -5.2C is added to a mixture of 45.0g of ice at 0C and 2000g of water at 95C?
Answers
Answered by
DrBob222
[45.8 g Al x specific heat Al x (Tf -Ti)]+ [45 g ice x heat fusion ice]+[45 g H2O from melted ice x specific heat water x (Tf - Ti)] + [2000 g H2O x specific heat water x (Tf-Ti)] = 0
Tf = final T; Ti = initial T. Solve for Tf. Post your work if you get stuck.
Tf = final T; Ti = initial T. Solve for Tf. Post your work if you get stuck.
Answered by
Lindsey
I know the specific heat for water is 4.184 and Al is 0.900. I don't know ice - our professor never went over that. Is it the same as water, or different?
Answered by
DrBob222
No it isn't; however, you don't need the specific heat of ice since the temperature of the ice is listed as zero C. What you need is the heat of fusion (to melt the ice) and that is 334 J/g.
Answered by
pigstatr
che che che chiia
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