Asked by Katie W

The measure of an angle SUT is twice m<RUS. if m<RUS=(18x-8)degrees and m<TUS=(4x + 16) degrees. Find m<RUT. This is an acute angle. Please help. I have tried figuring this problem out a million and one ways. Thanks
Answered by Katie W
The measure of an angle SUT is twice m∠RUS. if m∠RUS=(18x-8)degrees and m∠TUS=(4x + 16) degrees. Find m∠RUT. This is an acute angle. Please help. I have tried figuring this problem out a million and one ways. Thanks
Answered by Steve
well, surely you must recognize that ∠TUS ≅ ∠SUT, so that means that

4x+16 = 2(18x-8)
4x+16 = 36x-16
x = 1
So,
∠SUT = 20°
∠RUS = 10°

No idea what ∠RUT is, since you haven't said anything about the relative locations of the points or the angles.
Answered by sebastian s
its 30 degrees ya dink
Answered by Khaled
m<SUT فأوجد، m<SUT=(3x+6),m<RUS=(5x-4) اذا كان
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