Asked by anon
Find the number of negative integers greater than -500 that are divisible by 33.
Also find their sum.
How do I set up this problem?
Also find their sum.
How do I set up this problem?
Answers
Answered by
Reiny
let a = -33 , (the last one)
let d = -33 , going backwards
a+(n-1)d = appr -500
-33 + (n-1)(-33) = -500
-33 -33n + 33 = -500
-33n = -500
n = 15.15..
So there are 15 terms, and term(15) = -33 + 14(-33) = -495
so we have -495 , -462, -429, ... -66, -33
sum(15) = (15/2)(first + last) = (15/2)(-495-33) = -3960
let d = -33 , going backwards
a+(n-1)d = appr -500
-33 + (n-1)(-33) = -500
-33 -33n + 33 = -500
-33n = -500
n = 15.15..
So there are 15 terms, and term(15) = -33 + 14(-33) = -495
so we have -495 , -462, -429, ... -66, -33
sum(15) = (15/2)(first + last) = (15/2)(-495-33) = -3960
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